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383 lab 3 methods p 2

Submitted by liamharvey on Wed, 04/25/2018 - 13:58

            Using the online software Primer3, a primer for the gene was found. To do so, the genomic sequence of our unknown gene was put into the first box. The options for left and right primer was left selected. The sequence was named “MHN” in the Sequence ID box. In the box Product Size Range, 500-1000 was selected. Under General Primer Picking Conditions, the parameters were set to: Min = 20, Max = 27, Opt. = 23 for primer size and Min = 65 °C, Max= 70 °C, and Opt. = 67 °C in the “Primer Tm” box. A region of the gene was chosen to be amplified, this region had to include the mutation, was about 200bp from one of the primers and in a restriction site. Primer3 provides five primers, with the top one considered to be the best. With these five options, a primer was chosen based on how well it fit to the previous criteria. The chosen primers were then named “oMHN_L” (GTCCTCCGTCCACCAGTCCTT) and “oMHN_R” (GGTTCCAATGTCCAGCCTCTTGATTT) for the left and right primer’s respectively.

Denitrification Lab Results

Submitted by mkomtangi on Wed, 04/25/2018 - 13:45

For the Denitrification test, the results showed that there was nitrate present in both the rich and poor soil tubes because when nitrate reagent A and B were added to the Nitrate broth tubes, both turned red, meaning it is positive for nitrate. In addition,  a small amount of gas was found in the durham tubes meaning nitrate was broken down into gaseous products.

For both Proteus vulgaris and Pseudomonas aeruginosa nitrate was broken down into gaseous products because there was a large amount of gas in the durham tubes. In addition, when zinc was added to the tubes, there was no color change meaning it was a positive result and nitrate was broken down into a compound other than nitrite such as nitrogen gas.

 

Bio 288

Submitted by lgiron on Wed, 04/25/2018 - 13:27

In a normal respiratory system with average amounts of blood/blood pressure, the lungs function as oxygen intake centers for the body, as well as excretion of wastes, such as carbon dioxide. Without this constant cycle of intake and expulsion, humans would have a buildup of leftovers that form during the conversion of the nourishment we take in. The lungs do this by readily changing their volume to either force air from the environment in or out through the mouth. The oxygen within the air is then exchanged within the most miniscule parts of the lung, known as alveoli, via the hemoglobin within the red blood cells. Carbon dioxide is then put in its place, allowing blood cells to constantly perform this process and supply the body with the oxygen it need. This monitoring of the carbon dioxide levels within the blood also helps to control blood pH, which has a number of implications within the metabolic activities of other organs and tissues.

 

Deep Learning Assignment Draft

Submitted by lgorman on Wed, 04/25/2018 - 09:24
  1. After what step are the carbons of a fatty acid completely oxidized? (Lecture 22-Slide 11)

  2. This question is testing the students knowledge on the oxidation of fatty acids. More specifically, it asks the student to recall the steps of the oxidation, and know determine which step is completely oxidized.

  3. New Question: What step produces the most reduced electron carriers, and how many does it make for a (18:0) fatty acid?

    1. Acyl-CoA transport , 4 reduced electron carriers

    2. Beta oxidation, 36 reduced electron carriers

    3. Citric Acid Cycle, 36 reduced electron carriers (CORRECT)

    4. Citric Acid Cycle, 32 reduced electron carriers

  4. Why each answer is wrong/right:

    1. A is incorrect, because Acyl-CoA transport produces no reduced electron carriers, and 4 is the incorrect number.

    2. B is incorrect, because Beta oxidation does not produce the most reduced electron carriers, however 36 is the correct number.

    3. C is correct, because Citric Acid cycle step produces the most electron carriers, and 36 reduced electron carriers is the correct number.

    4. D is incorrect, while Citric acid cycle is the correct answer, 32 reduced electron carriers is the incorrect number.

Tetrahymena Seratonin Lab Introduction

Submitted by benjaminburk on Wed, 04/25/2018 - 04:53

Tetrahymena cells are unicellular predatory ciliates that produce both sexually and asexually. It is an excellent laboratory model because it possesses certain single cell advantages that are beneficial in the laboratory, while also sharing many genes with us multi-cellular animals (Cole 2000-2013). One interesting quality of the Tetrahymena is the way in which they feed. They feed in a process called phagocytosis, which results in the creation of small food vacuoles within the cell membrane (Coyne 2011). For the control group of this experiment the Tetrahymena cells were fed India ink and allowed to feed. Immediately after and then every five minutes for twenty minutes a random sample of Tetrahymena cells were taken and added to 50ul of glutaraldehyde, killing the cells without damaging the tissues. Once mixed, the Tetrahymena were put under a microscope and then ten randomly chosen cells had their black food vacuoles counted. The counts were averaged and the standard deviation calculated. Tetrahymena not randomly chosen were excluded from the experiment. For the experimental group the same exact procedure was followed, except for that initially along with introducing India Ink to the Tetrahymena we also placed 1ul of serotonin into the culture. We still took food vacuole counts of 10 randomly selected cells every five minutes for twenty minutes using the technique described in the control group procedure. In this experiment we decided to test the effects of serotonin on Tetrahymena food consumption. Based on previous experiments we are aware that serotonin stimulates the consumption of nutrients in Tetrahymena cells, therefore we hypothesized that the addition of the serotonin would lead to an increase in the number of food vacuoles observed compared to the amount observed in the control trials. With this being our hypothesis we hoped to find results that lead to higher vacuole count means for the group treated with serotonin, then the control group at all time points.

Yeast

Submitted by mglater on Wed, 04/25/2018 - 00:53

As expected, the H0 yeast matings served as controls, all resulting in white colonies. The H0 strain is unmutated, so the genes complemented any mutant that they were crossed with. Both of the unknown A type mutants gave the same results, meaning they share the same mutation. When crossed with HB2, they formed a white colony, meaning the genes complement each other. This means that the mutation in the A mutants is in Ade1. This is confirmed by the fact that the cross between the unknown mutants and HB1 results in little to no cell survival. The mutations are in the same gene, and therefore cannot complement each other. The two unknown alpha mutants also gave the same cross results and are therefore the same mutation. The unknown alpha mutants complemented with HA1 to produce a white colony, while they failed to complement with HA2. Following the same logic as with the A type mutants, this means that the mutation in the alpha yeast is in Ade2. Looking at the crosses between the A and alpha unknown mutants further supports this claim. The crosses between the unknown mutants all resulted in surviving white colonies, meaning that the genes complement. The only way for the mutations to complement are if the mutations are on different genes.

 

female P. hydrobothynus mate choice

Submitted by brettconnoll on Tue, 04/24/2018 - 22:02

Females will typically be won by males through battles over territory, however, males have also been seen to court young females by dancing for them in the water. They dance by doing flips, and spinning through the water and flashing their mane up and down above the water surface. There is also a behavior that males do that researchers have called the “wet noodle”. It involves the males sticking half of their body out of the water and shaking the upper half of their body back and forth making them look like a flailing noodle. Some males with very bright manes may be pretty enough to catch the attention of a female in the river system. If he can impress her with a brief dance in the water showing off his vibrant mane she may follow him back to his den. If the males den is high quality, then the female will stay with the male and he may be able to start his very own pride. 

fighting behavior of p. hydrobothynus

Submitted by brettconnoll on Tue, 04/24/2018 - 22:01

Males have an intricate way of fighting one another. First, the males will assess each other’s fitness. The male with the biggest brightest mane and largest canines may be able to intimidate the other male and may not have to fight at all. However, when intimidation doesn’t work males use their large powerful forelimbs, and long canines to inflict devastating blows to their opponents.

Plant Phys Draft 3

Submitted by lgorman on Tue, 04/24/2018 - 19:31

The stems that were being rotated were unable to feel a constant directional effect of gravity, while the non rotated stems did, which means that gravity had a 14.4° change on the root angle. Additionally, they placed one stem section upright and another stem section upside down in a beaker. After the roots were allowed to grow, they found that the stem grown upside down changed the root angle by 22.1°. This was because the plant was experiencing gravity from the opposite direction. Plants sense gravity using statoliths in their roots. By cutting a cross section of the root and staining them, the researchers found that statoliths are present in adventitious root nodes no matter the age of the node. Ultimately, gravity was found to have a moderate effect on the growth of the adventitious roots.

 

AB Intro Part 3

Submitted by malberigi on Tue, 04/24/2018 - 19:03

The three species of parrots we plan to study are the blue-fronted Amazon (Amazona aestiva), red-browed Amazon (Amazona rhodocorytha) and Kawall’s Amazon (Amazona kawalli).  All of these parrot species have experienced a decline in numbers over the last 25 years (Figueira, 2015) as a result of deforestation. The parrots species we plan to study prefer old-growth forests, the destruction of which has negatively impacted food availability and increased predation due to lack of canopy cover.  All three of these species will take and eat fruit, but the types of fruit preferred by each have not been studied yet.  Our research would shed light on the diets of these particular parrots, which could aid in conservation efforts.

 

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