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Elevator speech PP

Submitted by mrmoy on Thu, 04/26/2018 - 15:20

Our poster illustrates our study done on periphyton density and diversity in Fort River, located in Amherst, Massachusetts. The study was set up by making periphyton traps and placing them in three different locations along Fort River, each separated by roughly 100 meters.  Two sets of traps were put out at each of the three locations. The first set of traps was collected after 5 days and the second set of traps was collected after 15 days. After we collected the traps, we analyzed them under a microscope to identify the species diversity and to quantify species density. The diversity was simply calculated by looking at the different types of species, not by identifying them. The species density was calculated by counting all the individual organisms found on the microslides. After gathering all of our data, we found a moderate amount of diversity and a relatively high density. Based off this data, we can conclude that the pollution concentrations in Fort River are relatively low.

Methods Poster #3

Submitted by mrmoy on Thu, 04/26/2018 - 01:01

Upon collection of the traps, individual microslides were analyzed for density and diversity of species found using a standard microscope. The diversity of the species was calculated only by number of individual species observed, not by types of species. The density was analyzed by quantifying the number of different individual organism observed on each individual slide. This data was then organized into graphs and charts.

Methods Poster #2

Submitted by mrmoy on Thu, 04/26/2018 - 01:00

One end of a string was then tied around the slide, while the other end was tied around a branch. The traps were then submerged in >12 inches of water at the various locations. The first set of traps was collected after 5 days and the second set of traps was collected after 15 days.

Methods Poster

Submitted by mrmoy on Thu, 04/26/2018 - 01:00

Samples of the periphyton were collected in 3 different locations, separated by 100 m,along the Fort River in Amherst, Massachusetts. At each site, two sets of traps were put out. The traps were made of three glass microslides rubber banded together in a sandwich like fashion, and were separated by 1/2 inch cardboard cutouts.

Yeast Genetics Discussion PP

Submitted by mrmoy on Wed, 04/18/2018 - 21:09

Haploids HB1, HA1, and HA2 could not grow on their own as they could not synthesize their own adenine. This makes sense because they all had an ade mutation that makes them mutant deficient for adenine biosynthesis. Haploid HA0 could grow on its own, meaning that it can synthesize its own adenine. Again, this makes sense because this haploid strain had no mutations in any of its ade genes. The cross between HB1xHA1 did not proliferate. Because the cross contained one MATa and one MATα, sexual reproduction is possible. However, because it did not proliferate, it means that their alleles are not complementary. Next, the cross of HA1xHA2 did not proliferate. In this cross, both the haploids were MATa, therefore sexual reproduction is not possible and no proliferation is expected. The cross HB1xHA2 did proliferate. Both of these haploids could not grow on their own, however, when they were crossed they were able to proliferate. This cross contains one MATα and one MATa, thus the proliferation is caused by the complementation of their alleles. Finally, the cross of HB1xHA0 was able to proliferate. This cross needs to be furthered examined because although HB1 is MATα and HA0 is MATa, one cannot assume they sexually reproduced. As we know, HA0 is able to proliferate on its own, so either their alleles are complementary and it proliferated or it’s just HA0 proliferating and HB1 dying off.

Yeast Genetics Discussion #3

Submitted by mrmoy on Wed, 04/18/2018 - 21:08

Finally, the cross of HB1xHA0 was able to proliferate. This cross needs to be furthered examined because although HB1 is MATα and HA0 is MATa, one cannot assume they sexually reproduced. As we know, HA0 is able to proliferate on its own, so either their alleles are complementary and it proliferated or it’s just HA0 proliferating and HB1 dying off.

 

Yeast Genetics Discussion #2

Submitted by mrmoy on Wed, 04/18/2018 - 21:08

Next, the cross of HA1xHA2 did not proliferate. In this cross, both the haploids were MATa, therefore sexual reproduction is not possible and no proliferation is expected. The cross HB1xHA2 did proliferate. Both of these haploids could not grow on their own, however, when they were crossed they were able to proliferate. This cross contains one MATα and one MATa, thus the proliferation is caused by the complementation of their alleles.

Yeast Genetics Discussion

Submitted by mrmoy on Wed, 04/18/2018 - 21:07

Haploids HB1, HA1, and HA2 could not grow on their own as they could not synthesize their own adenine. This makes sense because they all had an ade mutation that makes them mutant deficient for adenine biosynthesis. Haploid HA0 could grow on its own, meaning that it can synthesize its own adenine. Again, this makes sense because this haploid strain had no mutations in any of its ade genes. The cross between HB1xHA1 did not proliferate. Because the cross contained one MATa and one MATα, sexual reproduction is possible. However, because it did not proliferate, it means that their alleles are not complementary.

Yeast Genetics Intro #2

Submitted by mrmoy on Wed, 04/18/2018 - 00:11

In this experiment, the yeast mutants requiring adenine was examined. Yeast cells cannot produce their own adenine, but if adenine is in the medium, then cells can convert it to adenosine monophosphate (AMP). The process of converting adenine to AMP requires multiple enzymes. As a result, any single mutation could result in an adenine requiring mutant or a mutant deficient for adenine biosynthesis.

 

Yeast Genetics Intro

Submitted by mrmoy on Wed, 04/18/2018 - 00:11

Throughout the history of science, Saccharomyces cerevisiae (yeast) has served as a model organism. Yeast is a unicellular, eukaryotic microorganism that can exist stably as both a haploid and diploid and can reproduce either sexually or asexually. When yeast are in the haploid state they exist as either the MATa or MATα. Yeast cells can remain in the haploid state, or one MATa and one MATα cell can sexually reproduce to produce a diploid cell.

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