DefB103 shows that we have do not have 3 G’s in a row, (shown in Figure 3). Since the data gets messy after the 2 G’s, we are favorable for the deletion and can conclude that our dog does not have wild-type DefB103 gene. However, at the third G, there is a heterozygous peak (A/G): there is one copy of the DNA strand that has the 5 G’s in a row, while another copy of DNA does not have 5 G’s in a row. Having a copy of both 5 Gs and 2 Gs means that we can conclude that we are heterozygous for β-Defensin, so our dog’s genotype is KB/kY at the K locus.
Schmutz and Dreger (n.d.) provide a table that answers the “phenotypes produced by the genotype interactions of ASIP, DEFB103, and MC1R in dogs.” Understanding that our dog has no e allele for MC1R, no ay allele for ASIP, and is heterozygous for DEFB103, we can look at the table to predict our dog’s phenotype. Figure 6 shows the table that presents our dog’s genotype.
From this table, we can conclude that our dog’s phenotype has a black coat with black lips and a black mouth.