AQ 11/20 Draft

DefB103 shows that we have do not have 3 G’s in a row, (shown in Figure 3). Since the data gets messy after the 2 G’s, we are favorable for the deletion and can conclude that our dog does not have wild-type DefB103 gene. However, at the third G, there is a heterozygous peak (A/G): there is one copy of the DNA strand that has the 5 G’s in a row, while another copy of DNA does not have 5 G’s in a row. Having a copy of both 5 Gs and 2 Gs means that we can conclude that we are heterozygous for β-Defensin, so our dog’s genotype is K^B/k^Y at the K locus.